5y^3dx-y^2(-2x+x^4y^2)=0

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Solution for 5y^3dx-y^2(-2x+x^4y^2)=0 equation:


Simplifying
5y3dx + -1y2(-2x + x4y2) = 0
5dxy3 + (-2x * -1y2 + x4y2 * -1y2) = 0
5dxy3 + (2xy2 + -1x4y4) = 0

Solving
5dxy3 + 2xy2 + -1x4y4 = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2xy2' to each side of the equation.
5dxy3 + 2xy2 + -2xy2 + -1x4y4 = 0 + -2xy2

Combine like terms: 2xy2 + -2xy2 = 0
5dxy3 + 0 + -1x4y4 = 0 + -2xy2
5dxy3 + -1x4y4 = 0 + -2xy2
Remove the zero:
5dxy3 + -1x4y4 = -2xy2

Add 'x4y4' to each side of the equation.
5dxy3 + -1x4y4 + x4y4 = -2xy2 + x4y4

Combine like terms: -1x4y4 + x4y4 = 0
5dxy3 + 0 = -2xy2 + x4y4
5dxy3 = -2xy2 + x4y4

Divide each side by '5xy3'.
d = -0.4y-1 + 0.2x3y

Simplifying
d = -0.4y-1 + 0.2x3y

Reorder the terms:
d = 0.2x3y + -0.4y-1

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